2x/x^2-7x-18=6x/x^2+x-2

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Solution for 2x/x^2-7x-18=6x/x^2+x-2 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/(x^2)-(7*x)-18 = x+(6*x)/(x^2)-2 // - x+(6*x)/(x^2)-2

(2*x)/(x^2)-(7*x)-x-((6*x)/(x^2))-18+2 = 0

(2*x)/(x^2)-7*x-x-6*x^-1-18+2 = 0

-8*x^1-4*x^-1-16*x^0 = 0

(-8*x^2-16*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(-8*x^2-16*x^1-4*x^0) = 0

x^1

-8*x^2-16*x-4 = 0

-8*x^2-16*x-4 = 0

DELTA = (-16)^2-(-8*(-4)*4)

DELTA = 128

DELTA > 0

x = (128^(1/2)+16)/(-8*2) or x = (16-128^(1/2))/(-8*2)

x = (8*2^(1/2)+16)/(-16) or x = (16-8*2^(1/2))/(-16)

x in { (8*2^(1/2)+16)/(-16), (16-8*2^(1/2))/(-16)}

x in { (8*2^(1/2)+16)/(-16), (16-8*2^(1/2))/(-16) }

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